document.write( "Question 1162677: A random sample of size n = 72 is taken from a population with mean μ = −13.7 and standard deviation σ = 9. [You may find it useful to reference the z table.]\r
\n" ); document.write( "\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( "a. Calculate the expected value and the standard error for the sampling distribution of the sample mean. (Negative values should be indicated by a minus sign. Round \"expected value\" to 1 decimal place and \"standard error\" to 4 decimal places.)\r
\n" ); document.write( "\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( "b. What is the probability that the sample mean is less than −14? (Round “z” value to 2 decimal places, and final answer to 4 decimal places.)\r
\n" ); document.write( "\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( "c. What is the probability that the sample mean falls between −14 and −13? (Do not round intermediate calculations. Round \"z\" value to 2 decimal places and final answer to 4 decimal places.)\r
\n" ); document.write( "\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #786620 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
E(X)= -13.7, the mean
\n" ); document.write( "SE is sigma/sqrt(n)=9/sqrt(72)=1.0607
\n" ); document.write( "z<(-14--13.7)/1.0607
\n" ); document.write( "<-0.3/1.0607
\n" ); document.write( "<-0.28. or -0.2828
\n" ); document.write( "probability is 0.3897
\n" ); document.write( "z for -13 is (0.7/1.0607)=0.6600\r
\n" ); document.write( "\n" ); document.write( "probability of z between -0.28 and 0.66 is 0.3567\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );