document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1162678>Question 1162678</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A random sample of size n = 120 is taken from a population with a population proportion p = 0.61. [You may find it useful to reference the z table.]\r<BR>\n" );
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document.write( "a. Calculate the expected value and the standard error for the sampling distribution of the sample proportion. (Round \"expected value\" to 2 decimal places and \"standard error\" to 4 decimal places.)\r<BR>\n" );
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document.write( "b. What is the probability that the sample proportion is between 0.60 and 0.70? (Round “z” value to 2 decimal places, and final answer to 4 decimal places.)\r<BR>\n" );
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document.write( "c. What is the probability that the sample proportion is less than 0.60? (Round “z” value to 2 decimal places, and final answer to 4 decimal places.)\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #786614 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=786614\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> E(X)=0.61<BR>\n" );
document.write( "SE is sqrt (0.61*0.39)/120=0.0445\r<BR>\n" );
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document.write( "z=(0.60-0.61)/0.0445 and (0.70-0.61)/0.0445 and that is z between -0.22 and 2.02 or probability of 0.5654\r<BR>\n" );
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document.write( "less than 0.60 is z <-0.22 or probability of 0.4129 </SPAN>\n" );
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