document.write( "Question 1162761: A random sample of size n = 62 is taken from a population of size N = 660 with a population proportion p = 0.63. [You may find it useful to reference the z table.]\r
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\n" ); document.write( "\n" ); document.write( "a-1. Is it necessary to apply the finite population correction factor?\r
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\n" ); document.write( "\n" ); document.write( " Yes
\n" ); document.write( " No\r
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\n" ); document.write( "\n" ); document.write( "a-2. Calculate the expected value and the standard error of the sample proportion. (Round \"expected value\" to 2 decimal places and \"standard error\" to 4 decimal places.)\r
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\n" ); document.write( "\n" ); document.write( "b. What is the probability that the sample proportion is less than 0.55? (Round ā€œzā€ value to 2 decimal places, and final answer to 4 decimal places.)\r
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Algebra.Com's Answer #786604 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
Yes, because 62 is more than 5% of 660.
\n" ); document.write( "E(X)=0.63
\n" ); document.write( "SE=SE prop.*fpc
\n" ); document.write( "=sqrt(0.63.*0.37/660) then *sqrt (598/660)=0.0179\r
\n" ); document.write( "\n" ); document.write( "z=(0.55-0.63)/0.0179)
\n" ); document.write( "=-4.47
\n" ); document.write( "probability=0.00001\r
\n" ); document.write( "\n" ); document.write( "The calculator will give a higher probability of 0.00001 but without doing the FPC.
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