document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=107884>Question 107884</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Thanks tutor for sloving this:<BR>\n" );
document.write( "lg(2x)-3lg2=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2F2%29lg%28x-3%29 ALIGN=MIDDLE  ALT=\"%281%2F2%29lg%28x-3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "lg means log with base 10<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #78656 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=78656\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> taking the antilog gives 2x/2^3=sqrt(x-3) ... squaring gives x^2/16=x-3\r<BR>\n" );
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document.write( "x^2-16x+48=0 ... (x-12)(x-4)=0 </SPAN>\n" );
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