document.write( "Question 1162717: Determine if the statement is true or false.
\n" ); document.write( "If the statement is false, then correct it and make it true.\r
\n" ); document.write( "\n" ); document.write( "The first term in the expansion of (a + b)^999 is a^999.
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Algebra.Com's Answer #786556 by Theo(13342)\"\" \"About 
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the statement is correct.
\n" ); document.write( "the first term in the expansion of (a+b)^999 is c(999,0) * a^999 * b^0.
\n" ); document.write( "this becomes (a + b)^999 = 1 * a^999 * 1 which becomes a^999.\r
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\n" ); document.write( "\n" ); document.write( "the general equation is (a+b)^n = the sum of c(n,k) * a^(n-k) * b^k for k = 0 to k = n\r
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\n" ); document.write( "\n" ); document.write( "note that c(n,k) is equal to n! / (k! * (n-k)!)\r
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\n" ); document.write( "\n" ); document.write( "an example will help clafify the equation.\r
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\n" ); document.write( "\n" ); document.write( "consider (a+b)^1
\n" ); document.write( "in this case, n = 1.
\n" ); document.write( "the formula states that (a+b)^n = the sum of c(n,k) * a^(n-k) * b^k for k = 0 to k = n
\n" ); document.write( "k will go from 0 to 1.
\n" ); document.write( "therefore, the formula becomes:
\n" ); document.write( "(a+b)^1 = c(1,0)*a^1*b^0 + c(1,1)*a^0*b^1
\n" ); document.write( "this becomes 1*a^1 + 1*b^1 which becomes a+b.\r
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\n" ); document.write( "\n" ); document.write( "this makes sense, since it should be intuitively obvious that (a+b)^1 = (a+b) since any quantity raise to the first power is that quantity itself.\r
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\n" ); document.write( "\n" ); document.write( "consider (a+b)^2
\n" ); document.write( "in this case, n = 2.
\n" ); document.write( "the formula states that (a+b)^n = the sum of c(n,k) * a^(n-k) * b^k for k = 0 to k = n
\n" ); document.write( "k will go from 0 to 2.
\n" ); document.write( "therefore, the formula becomes:
\n" ); document.write( "(a+b)^2 = c(2,0)*a^2*b^0 + c(2,1)*a^1*b^1 + c(2,2)*a^0*b^2
\n" ); document.write( "this becomes 1*a^2 + 2*a*b + 1*b^2 which becomes:
\n" ); document.write( "a^2 + 2ab + b^2\r
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\n" ); document.write( "\n" ); document.write( "this makes sense, since (a+b)^2 is equal to (a+b)*(a+b) which is equal to a*(a+b) + b*(a+b) which is equal to a^2 + ab + ab + b^2 which is equal to a^2 + 2ab + b^2\r
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\n" ); document.write( "\n" ); document.write( "you can confirm for (a+b)^3 by just following the formula.\r
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\n" ); document.write( "\n" ); document.write( "in all cases, however, you can see that the first term is a^n
\n" ); document.write( "when n is 1, the first term is a^1
\n" ); document.write( "then n is 2, the first term is a^2
\n" ); document.write( "when n is 999, the first term is a^999\r
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\n" ); document.write( "\n" ); document.write( "consider (a+b)^999
\n" ); document.write( "the first term is c(999,0)*a^999*b^0 which is equal to a^999.\r
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\n" ); document.write( "\n" ); document.write( "here's some references on the binomial theorem you might find useful.
\n" ); document.write( "pick the reference that makes the most sense to you.
\n" ); document.write( "don't break your brain.
\n" ); document.write( "if you are struggling with the reference, go on to the next one.
\n" ); document.write( "they all should be saying the same thing in different ways, some of which may be more understandable in terms of your thinking.\r
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\n" ); document.write( "\n" ); document.write( "http://hyperphysics.phy-astr.gsu.edu/hbase/alg3.html\r
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\n" ); document.write( "\n" ); document.write( "https://courses.lumenlearning.com/boundless-algebra/chapter/the-binomial-theorem/\r
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\n" ); document.write( "\n" ); document.write( "https://people.richland.edu/james/lecture/m116/sequences/binomial.html\r
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\n" ); document.write( "\n" ); document.write( "https://www.purplemath.com/modules/binomial.htm\r
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\n" ); document.write( "\n" ); document.write( "https://brilliant.org/wiki/binomial-theorem-n-choose-k/\r
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\n" ); document.write( "\n" ); document.write( "https://mathbitsnotebook.com/Algebra2/Polynomials/POBinomialTheorem.html\r
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