document.write( "Question 1162651: Let X be normally distributed with mean μ = 142 and standard deviation σ = 28. [You may find it useful to reference the z table.]\r
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document.write( "a. Find P(X ≤ 100). (Round \"z\" value to 2 decimal places and final answer to 4 decimal places.)\r
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document.write( "b. Find P(95 ≤ X ≤ 110). (Round \"z\" value to 2 decimal places and final answer to 4 decimal places.)\r
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document.write( "c. Find x such that P(X ≤ x) = 0.400. (Round \"z\" value and final answer to 3 decimal places.)\r
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document.write( "d. Find x such that P(X > x) = 0.800. (Round \"z\" value and final answer to 3 decimal places.)\r
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Algebra.Com's Answer #786488 by Boreal(15235) You can put this solution on YOUR website! z=(x-mean)/sd \n" ); document.write( "=(100-142)/28=-1.5 \n" ); document.write( "prob z< -1.5 is 0.0668\r \n" ); document.write( "\n" ); document.write( "z is -47/28 to -32/28 \n" ); document.write( "or -1.68 to -1.14 \n" ); document.write( "probability is 0.0807\r \n" ); document.write( "\n" ); document.write( "inv norm for 0.400 is z=-0.253 \n" ); document.write( "-0.253=(x-142)/28 \n" ); document.write( "-7.084=x-142 \n" ); document.write( "x=134.916\r \n" ); document.write( "\n" ); document.write( "z=0.842 \n" ); document.write( "0.842=(x-142)/28 \n" ); document.write( "x=165.576\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |