document.write( "Question 1162643: The length of each of a square is 1 cm more than the width of a rectangle. the length of hte rectangle is 1 cm less than twice its width. the perimeters of the two figures are equal. find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #786469 by josgarithmetic(39630)\"\" \"About 
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\n" ); document.write( "The length of each of a square is 1 cm more than the width of a rectangle. the length of hte rectangle is 1 cm less than twice its width. the perimeters of the two figures are equal. find the dimensions of the rectangle.
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\n" ); document.write( "\n" ); document.write( "w, the width of the rectangle
\n" ); document.write( "2w-1, the length of the rectangle
\n" ); document.write( "w+1, each side length of the square\r
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\n" ); document.write( "\n" ); document.write( "The perimeters given as equal.
\n" ); document.write( "\"2w%2B2%282w-1%29=4%28w%2B1%29\"
\n" ); document.write( "Simplify and solve,...
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