document.write( "Question 1162614: Find three consecutive integers such that the square of the sum of the smaller two is 105 more than the square of the largest. \n" ); document.write( "
Algebra.Com's Answer #786458 by ikleyn(52799)\"\" \"About 
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document.write( "Integers could be as  n-1, n, n+1.\r\n" );
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document.write( "\"%28%28n-1%29%2Bn%29%5E2=105%2B%28n%2B1%29%5E2\"\r\n" );
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document.write( "\"%282n-1%29%5E2=105%2Bn%5E2%2B2n%2B1\"\r\n" );
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document.write( "\"4n%5E2-4n%2B1=105%2Bn%5E2%2B2n%2B1\"\r\n" );
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document.write( "\"3n%5E2-4n-2n=105\"\r\n" );
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document.write( "\"3n%5E2-6n=105\"\r\n" );
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document.write( "\"n%5E2-2n=35\"\r\n" );
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document.write( "\"n%28n-2%29=35\"\r\n" );
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document.write( "This equation has TWO SOLUTIONS:  n = 7  and  n = -5.\r\n" );
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document.write( "So, there are TWO OPPORTUNITIES for the triple of the numbers:\r\n" );
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document.write( "    one triple is         6,  7,  8.\r\n" );
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document.write( "    the other triple is  -6, -5, -4.\r\n" );
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