document.write( "Question 1162614: Find three consecutive integers such that the square of the sum of the smaller two is 105 more than the square of the largest. \n" ); document.write( "
Algebra.Com's Answer #786453 by josgarithmetic(39620)\"\" \"About 
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Integers could be as n-1, n, n+1.\r
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\n" ); document.write( "\n" ); document.write( "\"%28%28n-1%29%2Bn%29%5E2=105%2B%28n%2B1%29%5E2\"
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\n" ); document.write( "\"%282n-1%29%5E2=105%2Bn%5E2%2B2n%2B1\"\r
\n" ); document.write( "\n" ); document.write( "\"4n%5E2-4n%2B1=105%2Bn%5E2%2B2n%2B1\"\r
\n" ); document.write( "\n" ); document.write( "\"3n%5E2-4n-2n=105\"\r
\n" ); document.write( "\n" ); document.write( "\"3n%5E2-6n=105\"\r
\n" ); document.write( "\n" ); document.write( "\"n%5E2-2n=35\"\r
\n" ); document.write( "\n" ); document.write( "\"n%28n-2%29=35\"\r
\n" ); document.write( "\n" ); document.write( "\"7%2A5=35\"\r
\n" ); document.write( "\n" ); document.write( "Middle Number could be 7.
\n" ); document.write( "Largest Number, 8.
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