document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1162586>Question 1162586</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mr. Lyons wishes to make a mixture of 12 pounds of tea worth $1.20 per pound by mixing tea worth $1.00 per pound with tea worth $1.30 per pound. What part of the mixture will be made up of the less expensive grade? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #786432 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=786432\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "You should understand how to solve this kind of problem by the standard algebraic method, as shown by the other tutor.<br><BR>\n" );
document.write( "However, if a formal algebraic solution is not required, look how easy it is to solve this problem:<br><BR>\n" );
document.write( "$1.20 is 2/3 of the way from $1.00 to $1.30.<BR>\n" );
document.write( "Therefore, 2/3 of the mixture is the tea worth $1.30 per pound.<br><BR>\n" );
document.write( "ANSWER: 2/3 of the 12 pounds, or 8 pounds, is the tea worth $1.30 per pound; the other 4 pounds is the tea worth $1.00 per pound.<br><BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "8(1.30)+4(1.00) = 10.40+4.00 = 14.40<BR>\n" );
document.write( "12(1.20) = 14.40<br><BR>\n" );
document.write( "You can use that method to solve ANY two-part mixture problem....<br><BR>\n" );
document.write( " </SPAN>\n" );
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