document.write( "Question 1162586: Mr. Lyons wishes to make a mixture of 12 pounds of tea worth $1.20 per pound by mixing tea worth $1.00 per pound with tea worth $1.30 per pound. What part of the mixture will be made up of the less expensive grade? \n" ); document.write( "

Algebra.Com's Answer #786421 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Mr. Lyons wishes to make a mixture of 12 pounds of tea worth $1.20 per pound by mixing tea worth $1.00 per pound with tea worth $1.30 per pound.
\n" ); document.write( " What part of the mixture will be made up of the less expensive grade?
\n" ); document.write( ":
\n" ); document.write( "let x = amt of $1 tea required
\n" ); document.write( "then
\n" ); document.write( "(12-x ) = $1.30 tea required
\n" ); document.write( ":
\n" ); document.write( "1x + 1.3(12-x) = 1.2(12)
\n" ); document.write( "x + 15.6 - 1.3x = 14.4
\n" ); document.write( "-.3x = 14.4 - 15.6
\n" ); document.write( "-.3x = -1.2
\n" ); document.write( "x = -1.2/-.3
\n" ); document.write( "x = +4 pounds of the cheap stuff
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check: (12 - 4 = 8 lb of $1.30 tea)
\n" ); document.write( "1(4) + 1.3(8) = 1.2(12)
\n" ); document.write( "4 + 10.4 = 14.4 \n" ); document.write( "

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