document.write( "Question 1162558: A candy distributor needs to mix a 30% fat-content chocolate with a 60% fat-content chocolate to create 100 kilograms of a 36% fat-content chocolate. How many kilograms of each kind of chocolate must they use? \n" ); document.write( "

Algebra.Com's Answer #786382 by greenestamps(13200) $\"\"$ $\"About$

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\n" ); document.write( "Let x be the number of kg of the 30% fat content chocolate; then the number of kg of 60% fat content chocolate is (100-x).

\n" ); document.write( "He is mixing x kg of 30% fat with (100-x) kg of 60% fat to obtain 100 kg of 36% fat:

\n" ); document.write( " $\".30%28x%29%2B.60%28100-x%29+=+.36%28100%29\"$

\n" ); document.write( "Solve using basic algebra (I leave that to you)....

\n" ); document.write( "Here is a quick and easy non-algebraic method you can use to find the solution to this problem, or any other two-part mixture problem.

\n" ); document.write( "(1) On a number line, 36% is 1/5 of the way from 30% to 60%. (From 30 to 60 is a difference of 30; from 30 to 36 is a difference of 6. 6/30 = 1/5.)

\n" ); document.write( "(2) That means 1/5 of the mixture is the chocolate with the higher percentage fat content.

\n" ); document.write( "ANSWER: 1/5 of the 100kg, or 20kg, of the 60%; the other 80kg of the 30%.

\n" ); document.write( "CHECK:
\n" ); document.write( ".60(20)+.30(80) 12+24 = 36
\n" ); document.write( ".36(100) = 36

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