document.write( "Question 1162558: A candy distributor needs to mix a 30% fat-content chocolate with a 60% fat-content chocolate to create 100 kilograms of a 36% fat-content chocolate. How many kilograms of each kind of chocolate must they use? \n" ); document.write( "
Algebra.Com's Answer #786381 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "Answer:
\n" ); document.write( "80 kilograms of the 30% fat content chocolate
\n" ); document.write( "20 kilograms of the 60% fat content chocolate\r
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\n" ); document.write( "\n" ); document.write( "Work Shown:\r
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\n" ); document.write( "\n" ); document.write( "We have two kinds of chocolate, which we'll call A and B
\n" ); document.write( "x = amount of chocolate A
\n" ); document.write( "y = amount of chocolate B
\n" ); document.write( "amounts are in kilograms
\n" ); document.write( "x+y = total amount of chocolate from both candies
\n" ); document.write( "x+y = 100, since we want 100 kg total
\n" ); document.write( "y = -x+100, solve for y\r
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\n" ); document.write( "\n" ); document.write( "0.30x = amount of pure fat from chocolate A
\n" ); document.write( "0.60y = amount of pure fat from chocolate B
\n" ); document.write( "0.30x+0.60y = total amount of pure fat from both chocolates combined
\n" ); document.write( "0.30x+0.60y = 0.36*100
\n" ); document.write( "0.30x+0.60y = 36
\n" ); document.write( "the expression 0.36*100 represents 36% of the total amount 100 kg is pure fat. So we have 36 kg of pure fat\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Plug in y = -x+100. Solve for x.
\n" ); document.write( "0.30x+0.60y = 36
\n" ); document.write( "0.30x+0.60( y ) = 36
\n" ); document.write( "0.30x+0.60( -x+100 ) = 36 ... replace y with -x+100
\n" ); document.write( "0.30x-0.60x+60 = 36 ... distribute
\n" ); document.write( "-0.30x+60 = 36
\n" ); document.write( "-0.30x = 36-60
\n" ); document.write( "-0.30x = -24
\n" ); document.write( "x = -24/(-0.30)
\n" ); document.write( "x = 80\r
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\n" ); document.write( "\n" ); document.write( "We can now find the value of y with this x value
\n" ); document.write( "y = -x+100
\n" ); document.write( "y = -80+100
\n" ); document.write( "y = 20
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