document.write( "Question 1162558: A candy distributor needs to mix a 30% fat-content chocolate with a 60% fat-content chocolate to create 100 kilograms of a 36% fat-content chocolate. How many kilograms of each kind of chocolate must they use? \n" ); document.write( "
Algebra.Com's Answer #786381 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Answer: \n" ); document.write( "80 kilograms of the 30% fat content chocolate \n" ); document.write( "20 kilograms of the 60% fat content chocolate\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "====================================================================\r \n" ); document.write( "\n" ); document.write( "Work Shown:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We have two kinds of chocolate, which we'll call A and B \n" ); document.write( "x = amount of chocolate A \n" ); document.write( "y = amount of chocolate B \n" ); document.write( "amounts are in kilograms \n" ); document.write( "x+y = total amount of chocolate from both candies \n" ); document.write( "x+y = 100, since we want 100 kg total \n" ); document.write( "y = -x+100, solve for y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "0.30x = amount of pure fat from chocolate A \n" ); document.write( "0.60y = amount of pure fat from chocolate B \n" ); document.write( "0.30x+0.60y = total amount of pure fat from both chocolates combined \n" ); document.write( "0.30x+0.60y = 0.36*100 \n" ); document.write( "0.30x+0.60y = 36 \n" ); document.write( "the expression 0.36*100 represents 36% of the total amount 100 kg is pure fat. So we have 36 kg of pure fat\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Plug in y = -x+100. Solve for x. \n" ); document.write( "0.30x+0.60y = 36 \n" ); document.write( "0.30x+0.60( y ) = 36 \n" ); document.write( "0.30x+0.60( -x+100 ) = 36 ... replace y with -x+100 \n" ); document.write( "0.30x-0.60x+60 = 36 ... distribute \n" ); document.write( "-0.30x+60 = 36 \n" ); document.write( "-0.30x = 36-60 \n" ); document.write( "-0.30x = -24 \n" ); document.write( "x = -24/(-0.30) \n" ); document.write( "x = 80\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We can now find the value of y with this x value \n" ); document.write( "y = -x+100 \n" ); document.write( "y = -80+100 \n" ); document.write( "y = 20 \n" ); document.write( " \n" ); document.write( " |