document.write( "Question 1162551: Find an equation in standard form of the parabola described.
\n" ); document.write( "Vertex at (-4, -4); passes through (0, 0)
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Algebra.Com's Answer #786371 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "There are two parabolas that satisfy the given conditions -- one opening up and another opening to the right.

\n" ); document.write( "Assuming a parabola that opens up....

\n" ); document.write( "The vertex form of the equation of a parabola is

\n" ); document.write( "\"%28y-k%29+=+a%28x-h%29%5E2\"

\n" ); document.write( "where the vertex is (h,k).

\n" ); document.write( "So the equation of this parabola is

\n" ); document.write( "\"%28y%2B4%29+=+a%28x%2B4%29%5E2\"

\n" ); document.write( "Use the coordinates of the known point to find the coefficient a:

\n" ); document.write( "\"%280%2B4%29+=+a%280%2B4%29%5E2\"
\n" ); document.write( "\"4+=+16a\"
\n" ); document.write( "\"a+=+1%2F4\"

\n" ); document.write( "The equation in vertex form is

\n" ); document.write( "\"%28y%2B4%29+=+%281%2F4%29%28x%2B4%29%5E2\"

\n" ); document.write( "Converting to standard form....

\n" ); document.write( "\"y%2B4+=+%281%2F4%29%28x%5E2%2B8x%2B16%29\"
\n" ); document.write( "\"y%2B4+=+%281%2F4%29x%5E2%2B2x%2B4\"
\n" ); document.write( "\"y+=+%281%2F4%29x%5E2%2B2x\"

\n" ); document.write( "A graph, showing the parabola passing through (0,0)....

\n" ); document.write( "\"graph%28400%2C400%2C-6%2C2%2C-6%2C2%2C%281%2F4%29x%5E2%2B2x%29\"

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