document.write( "Question 1162485: The value of a stock, A(x), over a year long period decreased and then increased according to the
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document.write( "quadratic function 𝐴(𝑥) = 0.75𝑥
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document.write( "2 − 6𝑥 + 20, where x represents the number of months passed since
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document.write( "you invested. The value of another stock, B(x), increased linearly according to the equation
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document.write( "𝐵(𝑥) = 2.75𝑥 + 1.50 over the same year. After how long are both stocks worth the same amount? \n" );
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Algebra.Com's Answer #786290 by Boreal(15235) You can put this solution on YOUR website! Set the two equal \n" ); document.write( "0.75x^2-6x+20=2.75x+1.50 \n" ); document.write( "0.75x^2-8.75x+18.5=0 \n" ); document.write( "x=(1/1.5)(8.75 +/- sqrt (76.56-55.5)); sqrt term is 4.59 \n" ); document.write( "the larger root is later in time and is (2/3)(20.22)=8.89 months\r \n" ); document.write( "\n" ); document.write( "(the earlier intersection was at 2.77 months)\r \n" ); document.write( "\n" ); document.write( "can also multiply through by 4 to get 3x^2-35x+74\r \n" ); document.write( "\n" ); document.write( " |