document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1162486>Question 1162486</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Assume that military aircraft use ejection seats designed for men weighing between 148.1 lb and 204 lb. If​ women's weights are normally distributed with a mean of 162.2 lb and a standard deviation of 46.8 ​lb, what percentage of women have weights that are within those​ limits? Are many women excluded with those​ specifications?<BR>\n" );
document.write( "The percentage of women that have weights between those limits is <BR>\n" );
document.write( "nothing​%.<BR>\n" );
document.write( "​(Round to two decimal places as​ needed.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #786289 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=786289\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> z=(x-mean)/sd<BR>\n" );
document.write( "so the first z is (148.1-162.2)/46.8 and the second is (204-162.2)/46.8, which are z s of -0.30 and 0.89 which is probability of 0.4312 or 43.12%\r<BR>\n" );
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document.write( "The calculator is nice for this 2nd VARS 2normalcdf ENTER (148.1,204,162.2,46.8) ENTER and probability of 0.4325 or 43.25%, the difference being rounding in the first.  Many are excluded with these specifications. </SPAN>\n" );
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