document.write( "Question 107867: This is for Introductory Algebra (College). Instructions are to FACTOR BY GROUPING. My instructor said to \"arbitrarily change a positive to a negative if necessary to get the correct answer\". That just doesn't make sense to me. I have a tendency to over-think things and I really want to know why and how I get to the correct answer. Is it really possible to just randomly make things up in math?????
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document.write( "I will show my work. Thank you in advance for any help you can give as you will likely be keeping me out of a straight-jacket at this point!\r
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document.write( "original problem to be factored by grouping:
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document.write( "p^2-2p-3rp+6r
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document.write( "my work:
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document.write( "(p^2-2p)-1(3rp+6r)
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document.write( "(p^2-2p)+(-3rp-6r)
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document.write( "p(p-2) -3r(p+2) OR p(p-2) +3r(-p-2) (THIS IS WHERE IT GOES DOWNHILL!!)
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document.write( "(?????)(p-3r) ... Final Answer is SUPPOSED to be (p-2)(p-3r)\r
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document.write( "Obviously I will never get that as an answer at the rate I am going.\r
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document.write( "Again, thank you for any possible help.\r
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Algebra.Com's Answer #78626 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! You are right; there are options at times but \n" ); document.write( "not arbitraries. \n" ); document.write( "======================== \n" ); document.write( "Your problem: \n" ); document.write( "original problem to be factored by grouping: \n" ); document.write( "p^2-2p-3rp+6r \n" ); document.write( "original problem to be factored by grouping: \n" ); document.write( "p^2-2p-3rp+6r \n" ); document.write( "p(p-2) -3r(p-2) \n" ); document.write( "(p-2)(p-3r) \n" ); document.write( "============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan \n" ); document.write( " |