document.write( "Question 1162443: if $1,000 is invested at an interest rate of 10% per year, compounded monthly, find the amount of the investment at the end of 4 years \n" ); document.write( "
Algebra.Com's Answer #786240 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "\"A+=+P%281%2Br%29%5En\"

\n" ); document.write( "A = future value
\n" ); document.write( "P = beginning principal
\n" ); document.write( "r = periodic interest rate
\n" ); document.write( "n = number of compounding periods

\n" ); document.write( "A is what we need to find
\n" ); document.write( "P is $1000
\n" ); document.write( "r is 1/12 of 10% (1/12 of 0.10), since the period is monthly
\n" ); document.write( "n is 4*12 = 48, the number of months (periods) in 4 years

\n" ); document.write( "\"A+=+1000%281%2B.10%2F12%29%5E48\"

\n" ); document.write( "Use a calculator....

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