document.write( "Question 107855: Stan invested $17,000, part at 18% and part at 4%. \r
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document.write( "If the total interest at the end of the year is $1,380, how much did he invest at each rate?
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Algebra.Com's Answer #78618 by scott8148(6628)![]() ![]() You can put this solution on YOUR website! let x=\"part @ 18%\", so 17000-x=\"part @ 4%\" ... (18%)(x)+(4%)(17000-x)=1380\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".18x+680-.04x=1380 ... .14x=700 \n" ); document.write( " |