document.write( "Question 107855: Stan invested $17,000, part at 18% and part at 4%. \r
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document.write( "If the total interest at the end of the year is $1,380, how much did he invest at each rate?
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Algebra.Com's Answer #78616 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! .18X+.04(17,000-X)=1,380 \n" ); document.write( ".18X+680-.04X=1,380 \n" ); document.write( ".14X=1,380-680 \n" ); document.write( ".14X=700 \n" ); document.write( "X=700/.14 \n" ); document.write( "X=5,000 INVESTED @ 18% \n" ); document.write( "17,000-5,000=12,000 INVESTED @ 4%. \n" ); document.write( "PROOF \n" ); document.write( ".18*5,000 +.04*12,000=1,380 \n" ); document.write( "900+480=1,380 \n" ); document.write( "1,380=1,380 \n" ); document.write( " |