document.write( "Question 1162375: given AB is parallel to DC, AB is congruent to DC, C is the midpoint of BE prove: AC is parallel to DE
\n" ); document.write( "Prove: triangle ABC is congruent to triangle to DCE
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\n" ); document.write( "C is the midpoint of BE, so B, C, and E are collinear.

\n" ); document.write( "Then, because AB is parallel to CD, angles ABC and DCE are congruent.

\n" ); document.write( "Then, since AB is congruent to CD and BC is congruent to CE, triangles ABC and DCE are congruent by SAS.

\n" ); document.write( "Triangles ABC and DCE are congruent, and angles BCA and CED are congruent.

\n" ); document.write( "The sum of angles ABC, BCA, and CAB is 180 degrees; the sum of angles BCA, ACD, and DCA is 180 degrees.

\n" ); document.write( "Therefore, angles ACD and CDA are congruent.

\n" ); document.write( "And, therefore, AC and DE are parallel.

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