document.write( "Question 1162375: given AB is parallel to DC, AB is congruent to DC, C is the midpoint of BE prove: AC is parallel to DE
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document.write( "Prove: triangle ABC is congruent to triangle to DCE \n" );
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Algebra.Com's Answer #786154 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "C is the midpoint of BE, so B, C, and E are collinear. \n" ); document.write( "Then, because AB is parallel to CD, angles ABC and DCE are congruent. \n" ); document.write( "Then, since AB is congruent to CD and BC is congruent to CE, triangles ABC and DCE are congruent by SAS. \n" ); document.write( "Triangles ABC and DCE are congruent, and angles BCA and CED are congruent. \n" ); document.write( "The sum of angles ABC, BCA, and CAB is 180 degrees; the sum of angles BCA, ACD, and DCA is 180 degrees. \n" ); document.write( "Therefore, angles ACD and CDA are congruent. \n" ); document.write( "And, therefore, AC and DE are parallel. \n" ); document.write( " \n" ); document.write( " |