document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=107853>Question 107853</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could someone please explain to me how to find an algebraic expression to calculate the nth term of the following sequence?:<BR>\n" );
document.write( "2, 5, 11, 23, 47, 95, 191\r<BR>\n" );
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document.write( "I know that the equation to continue the series is 2x+1, but I've tried for 2 hours to figure out an equation for the nth term, and all I've gotten is frustrated!\r<BR>\n" );
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document.write( "Thanks so much for any help!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #78615 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=78615\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> look at the differences between terms ... 3, 6, 12, 24, 48, 96<BR>\n" );
document.write( "... the difference is doubling, so 2 is being raised to a sequential power\r<BR>\n" );
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document.write( "look at the terms ... 3-1, 3*2-1, 3*4-1, 3*8-1, 3*16-1, etc.<BR>\n" );
document.write( "... 3*(2^0)-1, 3*(2^1)-1, 3*(2^2)-1, 3*(2^3)-1, etc. </SPAN>\n" );
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