document.write( "Question 1162279: In a random sample of 500 observations, we found the proportion of success to be 48%. Estimate with 95% confidence the population proportion success. \n" ); document.write( "
Algebra.Com's Answer #786066 by AnlytcPhil(1806)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "On your TI-84 calculator,\r\n" );
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document.write( "Press stat \r\n" );
document.write( "Press the right arrow key to highlight TESTS\r\n" );
document.write( "Use the down arrow key to scroll down to  A:1-PropZint\r\n" );
document.write( "Press enter\r\n" );
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document.write( "       1-PropZInt\r\n" );
document.write( "x:0.48*500        <--Press the down arrow, it will change to x:240  \r\n" );
document.write( "n:500             <--Press the down arrow\r\n" );
document.write( "C-Level:0.95      <--Press the down arrow \r\n" );
document.write( "Calculate         <--Press enter\r\n" );
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document.write( "       1-PropZint\r\n" );
document.write( "(0.43621,0.52379)\r\n" );
document.write( "p=0.48\r\n" );
document.write( "n=500\r\n" );
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document.write( "The answer is (0.43621,0.52379) or 0.43621 < p < 0.52379\r\n" );
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document.write( "Round off as your teacher told you.\r\n" );
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document.write( "Edwin

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