document.write( "Question 1162288: Tanner has $5.40 in nickels and quarters. Suppose he has 18 more nickels than quarters. \n" ); document.write( "
Algebra.Com's Answer #786065 by AnlytcPhil(1810)\"\" \"About 
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document.write( "Without using algebra:\r\n" );
document.write( "Those 18 extra nickels are worth 18×$0.05 = $0.90. So if he took out the 18\r\n" );
document.write( "extra nickels, he'd have only $5.40-$0.90 = $4.50 left with the same number\r\n" );
document.write( "of nickels as quarters. If he then were to pair them up by taping a nickel\r\n" );
document.write( "to each quarter, he'd have a bunch of quarter-nickel pairs each worth $0.30.\r\n" );
document.write( "$4.50÷$.30 = 15 quarter-nickel pairs.  So there are 15 quarters and 18\r\n" );
document.write( "additional nickels, or 15+18 = 33 nickels.\r\n" );
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document.write( "Using algebra:\r\n" );
document.write( "Let the number of quarters = q\r\n" );
document.write( "Then the number of nickels = q+18\r\n" );
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document.write( "   $0.25q + $0.05(q+18) = $5.40\r\n" );
document.write( "$0.25q + $0.05q + $0.90 = $5.40 \r\n" );
document.write( "         $0.30q + $0.90 = $5.40\r\n" );
document.write( "                 $0.30q = $4.50\r\n" );
document.write( "                      q = $4.50/$0.30\r\n" );
document.write( "                      q = 15\r\n" );
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document.write( "The number of quarters = q = 15\r\n" );
document.write( "The number of nickels = q+18 = 15+18 = 33\r\n" );
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document.write( "Edwin
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