document.write( "Question 1162265: A farm co-op wants to grow corn and soybeans. Each acre of corn requires 7 gallons of fertilizer and 0.50 hours to harvest. Each acre of soybeans requires 3 gallons of fertilizer and 1 hour to harvest. The co-op has available at most 40,500 gallons of fertilizer and 5,250 hours of labor for harvesting. If the profits per acre are $50 for corn and $45 for soybeans, how many acres of each should the co-op plant to maximize their profit? What is the maximum profit?\r
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Algebra.Com's Answer #786053 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
x = number of acres of corn.
\n" ); document.write( "y = number of acres of soybeans.\r
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\n" ); document.write( "\n" ); document.write( "make a table as shown below:\r
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document.write( "                             x                   y\r\n" );
document.write( "                           corn              soybeans\r\n" );
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document.write( "fertilizer gallons           7                   3         <= 40,500\r\n" );
document.write( "harvest hours                .5                  1         <= 5,250\r\n" );
document.write( "profit                       50                  45        maximize\r\n" );
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\n" ); document.write( "\n" ); document.write( "using the desmos.com calculator, graph the opposite of the constraints and then evaluate the objective function at the corner points of the feasible region.\r
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\n" ); document.write( "\n" ); document.write( "the constraint functions are:\r
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\n" ); document.write( "\n" ); document.write( "7x + 3y <= 40,500
\n" ); document.write( ".5x + y <= 5250
\n" ); document.write( "x,y >= 0\r
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\n" ); document.write( "\n" ); document.write( "the objective function is:\r
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\n" ); document.write( "\n" ); document.write( "profit = 50x + 45y\r
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\n" ); document.write( "\n" ); document.write( "you are graphing the OPPOSITE of the constraint inequalities.\r
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\n" ); document.write( "\n" ); document.write( "here's what the graph looks like:\r
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\n" ); document.write( "\n" ); document.write( "maximum profit is at the point (4500,3000).
\n" ); document.write( "profit is 50*4500 + 45*3000 = 360,000
\n" ); document.write( "gallons of fertilizer used are 4500*7 + 3000*3 = 40,500 <= 40,500
\n" ); document.write( "hours of labor = 4500*.5 + 3000*1 = 5250 <= 5250\r
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\n" ); document.write( "\n" ); document.write( "looks like all the available resources were used when the maximum profit was attained.\r
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