document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1162264>Question 1162264</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many milligrams of uranium with 72% purity and 84.8% must be mixed to obtain 9 milligrams with 80% purity? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #786043 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=786043\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "If a formal algebraic solution is not required, here is a quick and easy informal path to solving a \"mixture\" problem like this.<br><BR>\n" );
document.write( "(1) The 80% target percentage is 5/8 of the way from 72% to 84.8%:<BR>\n" );
document.write( "72 to 84.8 is a difference of 12.8<BR>\n" );
document.write( "72 to 80 is a difference of 8<BR>\n" );
document.write( "8/12.8 = 80/128 = 5/8<br><BR>\n" );
document.write( "That means 5/8 of the mixture needs to be the higher percentage ingredient.<br><BR>\n" );
document.write( "ANSWER: 5/8 of 9mg = 45/8 = 5.625mg of 84.8% purity; the other 3.375mg of 72%.<br><BR>\n" );
document.write( "CHECK:<br><BR>\n" );
document.write( "0.0848(5.625)+.072(3.375) = .477+.243 = .72<br><BR>\n" );
document.write( ".08(9) = .72<br><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );