document.write( "Question 107850: Solve for y:
\n" ); document.write( "2x-3y=12\r
\n" ); document.write( "\n" ); document.write( "This is what I got:
\n" ); document.write( "3y=12-2x
\n" ); document.write( "y=12-2x over
\n" ); document.write( " 3
\n" ); document.write( "y=2-4x over
\n" ); document.write( " 3
\n" ); document.write( "

Algebra.Com's Answer #78604 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
Your first problem was with the sign on the 3y term in your first step.\r
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\n" ); document.write( "\n" ); document.write( "\"2x-3y=12\"
\n" ); document.write( "\"-3y=12-2x\": The minus sign needs to stay with the 3y term.
\n" ); document.write( "\"y=%2812-2x%29%2F-3\": Divide by -3
\n" ); document.write( "\"y=-4%2B2x%2F3\": Or you can write this more neatly as:
\n" ); document.write( "\"y=2x%2F3-4\"\r
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