document.write( "Question 1162264: How many milligrams of uranium with 72% purity and 84.8% must be mixed to obtain 9 milligrams with 80% purity? \n" ); document.write( "
Algebra.Com's Answer #786031 by ankor@dixie-net.com(22740)\"\" \"About 
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How many milligrams of uranium with 72% purity and 84.8% must be mixed to obtain 9 milligrams with 80% purity?
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\n" ); document.write( "let x = amt of 84.8% uranium
\n" ); document.write( "Total is to be 9 mg, therefore
\n" ); document.write( "(9-x) = amt of 72%
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\n" ); document.write( "Mixture equation in decimal form
\n" ); document.write( ".848x + .72(9-x) = .80(9)
\n" ); document.write( ".848x + 6.48 - .72x = 7.2
\n" ); document.write( ".848x - .72x = 7.2 - 6.48
\n" ); document.write( ".128x = .72
\n" ); document.write( "x = .72/.128
\n" ); document.write( "x = 5.625 mg of 84.8% uranium
\n" ); document.write( "then
\n" ); document.write( "9 - 5.625 = 3.375 mg of 72%
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\n" ); document.write( "Check on your calc
\n" ); document.write( ".848(5.625) + .72(3.375) = .8(9)
\n" ); document.write( "4.77 + 2.43 = 7.2 \n" ); document.write( "
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