document.write( "Question 1162246: A coin collector has 19 dimes and nickels with a total face value of $1.55. (They are actually worth a lot more.) How many of each coin does she have? \n" ); document.write( "
Algebra.Com's Answer #786016 by greenestamps(13203)\"\" \"About 
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\n" ); document.write( "A student just learning algebra should certainly know how to solve the problem using formal algebra, as shown by the other tutor.

\n" ); document.write( "But solving a problem like this informally, with logical reasoning and simple arithmetic, is good mental exercise. It might go something like this:

\n" ); document.write( "(1) If all 19 coins were nickels, the total face value would be 95 cents; the actual value is $1.55, or 155 cents. The difference is 60 cents.
\n" ); document.write( "(2) Exchanging a nickel for a dime keeps the number of coins the same and increases the face value by 5 cents.
\n" ); document.write( "(3) The number of times a nickel needs to be exchanged for a dime, to make up the difference of 60 cents, is 60/5 = 12.
\n" ); document.write( "(4) Therefore, the collection contains 12 dimes and 19-12 = 7 nickels.

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