document.write( "Question 1162245: Kelly has a collection of nickels, dimes, and quarters with a total value of $6.10. There are four more nickels than dimes and twice as many quarters as nickels. How many of each coin is in her collection? \n" ); document.write( "
Algebra.Com's Answer #785999 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
n = number of nickels, d = number of dimes, q = number of quarters.
\n" ); document.write( "the value of a nickel is.05, the balue of a dime is .1, the value of a quarter is .25
\n" ); document.write( ".05 * n + .1 * d + .25 * q = 6.10
\n" ); document.write( "n = d + 4
\n" ); document.write( "q = 2 * n
\n" ); document.write( "you want to make all values in terms of nickels.
\n" ); document.write( "from n = d + 4, you get d = n - 4
\n" ); document.write( "you already have q = 2 * n
\n" ); document.write( "the equation of .05 * n + .1 * d + .25 * q = 6.10 becomes:
\n" ); document.write( ".05 * n + .1 * (n - 4) + .25 * (2 * n) = 6.10
\n" ); document.write( "simplify to get:
\n" ); document.write( ".05 * n + .1 * n - .4 + .5 * n = 6.10
\n" ); document.write( "combine like terms to get:
\n" ); document.write( ".65 * n - .4 = 6.10
\n" ); document.write( "add .4 to both sides of the equation to get:
\n" ); document.write( ".65 * n = 6.5
\n" ); document.write( "solve for n to get:
\n" ); document.write( "n = 10
\n" ); document.write( "since d = n - 4, then d = 6
\n" ); document.write( "since q = 2 * n, then q = 20
\n" ); document.write( "you have 10 nickels, 6 dimes, and 20 quarters.
\n" ); document.write( "their total value is 10 * .05 + 6 * .1 + 20 * .25 = 6.10.
\n" ); document.write( "10 nickels, 6 dimes, and 20 quarters is your solution.
\n" ); document.write( " \n" ); document.write( "
\n" );