document.write( "Question 1162242: An alloy is composed of the following:\r
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document.write( "An amount of copper.\r
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document.write( "An amount of nickel equal to 62.5% of the copper.\r
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document.write( "An amount of zinc equal to 33.3% of the copper.\r
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document.write( "An amount of lead equal to 5% of the copper.\r
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document.write( "The total alloy weighs 40 1/6 lbs.\r
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document.write( "Determine amount of each part.\r
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document.write( "Unsure how to solve. \n" );
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Algebra.Com's Answer #785983 by greenestamps(13203) You can put this solution on YOUR website! \n" ); document.write( "Let x be the amount (pounds) of copper. \n" ); document.write( "Then express the amount of each other element in terms of x. \n" ); document.write( "nickel: 62.5% of x, which is (5/8)x \n" ); document.write( "zinc: 33.3% of x, which is (presumably) (1/3)x \n" ); document.write( "lead: 5% of x, which is (1/20)x \n" ); document.write( "The total weight is 40 1/6 pounds, or (241/6) pounds: \n" ); document.write( " \n" ); document.write( "Multiply through by the least common denominator, which is 120: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "ANSWERS: \n" ); document.write( "copper: x = 20 pounds \n" ); document.write( "nickel: (5/8)x = 12 1/2 pounds \n" ); document.write( "zinc: (1/3)x = 6 2/3 pounds \n" ); document.write( "lead: (1/20)x = 1 pound \n" ); document.write( "CHECK: \n" ); document.write( "20 + 12 1/2 + 6 2/3 + 1 = 39+3/6+2/6 = 40 + 1/6 \n" ); document.write( " \n" ); document.write( " |