document.write( "Question 1162221: Solve for x algebraically: 3^𝑥 + 3^𝑥+1 = 11^𝑥 + 11^𝑥+1
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Algebra.Com's Answer #785963 by ikleyn(53765)\"\" \"About 
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document.write( "\"3%5Ex\" + \"3%5E%28x%2B1%29\" = \"11%5Ex\" + \"11%5E%28x%2B1%29\"\r\n" );
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document.write( "\"3%5Ex%2A%281%2B3%29\" = \"11%5Ex%2A%281%2B11%29\"\r\n" );
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document.write( "\"4%2A3%5Ex\" = \"12%2A11%5Ex\"\r\n" );
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document.write( "\"3%5Ex%2F11%5Ex\" = \"12%2F4\"\r\n" );
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document.write( "\"%283%2F11%29%5Ex\" = 3\r\n" );
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document.write( "Take logarithm base 3 of both sides\r\n" );
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document.write( "\"x%2Alog%283%2C%283%2F11%29%29\" = \"log%283%2C%283%29%29\"\r\n" );
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document.write( "\"x%2A%281-log%283%2C%2811%29%29%29\" = 1\r\n" );
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document.write( "x = \"1%2F%281-log%283%2C%2811%29%29%29\".      ANSWER\r\n" );
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