document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=107834>Question 107834</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the number of hours it will take an automobile going forty-five miles per hour to catch up with an automobile moving at thirty miles per hour if the slower automobile starts one hour before the faster automobile? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #78596 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=78596\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the slower automobile has a 30 mi. (30 mph X 1 h) head start\r<BR>\n" );
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document.write( "the faster automobile catches up at the rate of 15 mph (45 mph - 30 mph)\r<BR>\n" );
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document.write( "so it will take the faster automobile 2 h. (30 mi / 15 mph) to catch the slower automobile </SPAN>\n" );
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