document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1162164>Question 1162164</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the number of terms in the arithmetic progression 1, 3 , 5,....101<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #785925 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13206)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=785925\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Another path to the answer without algebra, accessible to young students....<br><BR>\n" );
document.write( "The first term is 1; each term is 2 more than the preceding term; the last term is 101.<br><BR>\n" );
document.write( "How many 2's do you need to add to the first term, 1, to get the last term, 101?  Answer: (101-1)/2 = 100/2 = 50.<br><BR>\n" );
document.write( "So there are 50 terms after the first one; that means there are 51 terms.<br><BR>\n" );
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