document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1162180>Question 1162180</A>: <I><SPAN STYLE=\"word-break: break-all;\"> determine k such that g(x)=3x^2+8x+k intersects f(x)=2x-1 at ine point. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #785907 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=785907\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find a place where the line 2x-1 is tangent to the curve.\r<BR>\n" );
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document.write( "Want one point only, where the slopes are the same, 2, because that is the slope of the line<BR>\n" );
document.write( "find slope of the quadratic: derivative is 6x+8, and that equals 2 when x=-1<BR>\n" );
document.write( "when x=-1, 2x-1=-3<BR>\n" );
document.write( "so the point is (-1, -3) for the line.  It has to be for the quadratic as well.<BR>\n" );
document.write( "when x=-1, the quadratic is 3-8+k and that has to equal -3<BR>\n" );
document.write( "-5+k=-3<BR>\n" );
document.write( "k=2\r<BR>\n" );
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