document.write( "Question 1162137: From a group of 6 girls and 7 boys, how many 5-member committees consist of
\n" ); document.write( "(a) 3 girls and 2 boys
\n" ); document.write( "(b) 3 boys and 2 girls
\n" ); document.write( "(c) members of the same sex
\n" ); document.write( "(d) more boys than girls.\r
\n" ); document.write( "\n" ); document.write( "One of the boy cannot get along with one of the girl. Find the number of committees which include this particular boy or girl, but not both.\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #785866 by Edwin McCravy(20054)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "For this problem, remember that AND means to multiply and OR means to add.\r\n" );
document.write( "
From a group of 6 girls and 7 boys, how many 5-member committees consist of
\n" ); document.write( "(a) 3 girls and 2 boys
\r\n" );
document.write( "\r\n" );
document.write( "(6 girls CHOOSE 3) AND (7 boys CHOOSE 2) = (6C3)∙(7C2) = 20∙21 = 420 \r\n" );
document.write( "\r\n" );
document.write( "------------------------------------------------------------\r\n" );
document.write( "\r\n" );
document.write( "
(b) 3 boys and 2 girls
\r\n" );
document.write( "\r\n" );
document.write( "(7 boys CHOOSE 3) AND (6 girls CHOOSE 2) = (7C3)∙(6C2) = 35∙15 = 525 \r\n" );
document.write( "\r\n" );
document.write( "------------------------------------------------------------\r\n" );
document.write( "\r\n" );
document.write( "
(c) members of the same sex
\r\n" );
document.write( "\r\n" );
document.write( "(6 girls CHOOSE 5) OR (7 boys CHOOSE 5) = (6C5) + (7C5) = 6 + 21 = 26 \r\n" );
document.write( "\r\n" );
document.write( "------------------------------------------------------------\r\n" );
document.write( "\r\n" );
document.write( "
(d) more boys than girls.
\r\n" );
document.write( "\r\n" );
document.write( "(6 girls CHOOSE 2) AND (7 boys CHOOSE 3) = (6C2)∙(7C2) = 15∙35 = 525\r\n" );
document.write( "\r\n" );
document.write( "              OR\r\n" );
document.write( "\r\n" );
document.write( "(6 girls CHOOSE 1) AND (7 boys CHOOSE 4) = (6C1)∙(7C4) = 6∙35 = 210 \r\n" );
document.write( "\r\n" );
document.write( "              OR\r\n" );
document.write( "\r\n" );
document.write( "7 boys CHOOSE 5 = 7C5 = 21  \r\n" );
document.write( "\r\n" );
document.write( "Answer: 525 + 210 + 21 = 756\r\n" );
document.write( "\r\n" );
document.write( "------------------------------------------------------------\r\n" );
document.write( "\r\n" );
document.write( "
One of the boys cannot get along with one of the girls. Find the
\n" ); document.write( "number of committees which include this particular boy or girl, but not
\n" ); document.write( "both.
\r\n" );
document.write( "\r\n" );
document.write( "Number of committees that leave out the particular girl:\r\n" );
document.write( "\r\n" );
document.write( "12 people CHOOSE 5 = 12C5 = 792\r\n" );
document.write( "\r\n" );
document.write( "minus the number that leave out both the particular boy and girl:\r\n" );
document.write( "\r\n" );
document.write( "11 people CHOOSE 5 = 11C5 = 462\r\n" );
document.write( "\r\n" );
document.write( "That's 792-462 = 330\r\n" );
document.write( "\r\n" );
document.write( "OR\r\n" );
document.write( "\r\n" );
document.write( "Number of committees that leave out the particular boy:\r\n" );
document.write( "\r\n" );
document.write( "12 people CHOOSE 5 = 12C5 = 792\r\n" );
document.write( "\r\n" );
document.write( "minus the number that leave out both the particular boy and girl:\r\n" );
document.write( "\r\n" );
document.write( "11 people CHOOSE 5 = 11C5 = 462\r\n" );
document.write( "\r\n" );
document.write( "That's 792-462 = 330\r\n" );
document.write( "\r\n" );
document.write( "Answer: 330 + 330 = 660\r\n" );
document.write( "\r\n" );
document.write( "------------------------------------------------------------\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\n" ); document.write( "
\n" );