document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=15943>Question 15943</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help on this problem:\r<BR>\n" );
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document.write( "Three times the greatest of three consucutive intergers exceeds twice the least by 38.  Find the intergers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #7858 by </B><A HREF=/tutors/aboutme.mpl?userid=pwac><B>pwac(253)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=pwac><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=7858\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let 1st integer=x<BR>\n" );
document.write( "so 2nd =x+1<BR>\n" );
document.write( "and 3rd=x+2<BR>\n" );
document.write( "so 3 times greatest(x+2)= 2 times least(x)plus 38.This looks like:<BR>\n" );
document.write( "3(x+2)=2x+38 Remove bracket by multiplying by the 3<BR>\n" );
document.write( "3x+6=2x+38 Subtract 2x from both sides<BR>\n" );
document.write( "x+6=38 subtract 6 from both sides<BR>\n" );
document.write( "x=32<BR>\n" );
document.write( "which is the smallest of the 3 integers you are looking for<BR>\n" );
document.write( "Pete </SPAN>\n" );
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