document.write( "Question 1161734: In a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (beforeminusafter) in their levels of LDL cholesterol (in mg/dL) have a mean of 5.4 and a standard deviation of 16.4. Construct a 95% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? \n" ); document.write( "
Algebra.Com's Answer #785766 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! The 95% CI half interval is t (0.975, df=48)*s/sqrt (n) \n" ); document.write( "t=2.01 \n" ); document.write( "half-interval is 2.01*16.4/7=4.71 \n" ); document.write( "add to and subtract from mean \n" ); document.write( "(0.69, 10.11) mg % are units \n" ); document.write( "The CI suggests that there is a positive change since 0 is not in the confidence interval. It would suggest that garlic does help reduce LDL. \n" ); document.write( " |