document.write( "Question 1161734: In a test of the effectiveness of garlic for lowering​ cholesterol, 49 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes ​(beforeminus​after) in their levels of LDL cholesterol​ (in mg/dL) have a mean of 5.4 and a standard deviation of 16.4. Construct a 95​% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL​ cholesterol? \n" ); document.write( "
Algebra.Com's Answer #785766 by Boreal(15235)\"\" \"About 
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The 95% CI half interval is t (0.975, df=48)*s/sqrt (n)
\n" ); document.write( "t=2.01
\n" ); document.write( "half-interval is 2.01*16.4/7=4.71
\n" ); document.write( "add to and subtract from mean
\n" ); document.write( "(0.69, 10.11) mg % are units
\n" ); document.write( "The CI suggests that there is a positive change since 0 is not in the confidence interval. It would suggest that garlic does help reduce LDL.
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