document.write( "Question 1162038: A woman earns $960 in interest from two accounts in a year. If she has three times as much invested at 9% as she does at 5%, how much does she have in each account? \n" ); document.write( "
Algebra.Com's Answer #785723 by greenestamps(13209)\"\" \"About 
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\n" ); document.write( "If she has three times as much invested at 9% as at 5%, then the average rate is 8%:

\n" ); document.write( "\"%283%289%29%2B1%285%29%29%2F4+=+%2827%2B5%29%2F4+=+8\"

\n" ); document.write( "Since the average interest rate was 8% and the interest was $960, the amount invested was $960/.08 = $12,000.

\n" ); document.write( "Then again since she had three times as much invested at 9% as at 5%, since the total was $12,000 the two amounts were $9000 at 9% and $3000 at 5%.

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