document.write( "Question 1162001: Use two equations in two variables to solve the problem.\r
\n" ); document.write( "\n" ); document.write( "The perimeter of the rectangular garden shown below is 80 meters. The width of the garden is two-thirds its length, find its area A. \n" ); document.write( "

Algebra.Com's Answer #785667 by ikleyn(52778) $\"\"$ $\"About$

You can put this solution on YOUR website!
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document.write( "These equations are\r\n" );
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document.write( "    2x + 2y = 80           (1)\r\n" );
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document.write( "     y = ,           (2)\r\n" );
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document.write( "where x is the length and y is the width of the garden.\r\n" );
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document.write( "From equation (2), you have  \r\n" );
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document.write( "    3y = 2x.                (3)\r\n" );
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document.write( "In equation (1), replace 2x by 3y, based on (3).  You will get then\r\n" );
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document.write( "   3y + 2y = 80\r\n" );
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document.write( "   5y      = 80\r\n" );
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document.write( "    y      = 80/5 = 16.\r\n" );
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document.write( "So, the width is 16 meters.\r\n" );
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document.write( "Then the length is   =  = 24 meters.\r\n" );
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document.write( "ANSWER.  The length is 24 m;  the width is  16 m.\r\n" );
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document.write( "CHECK.   16 m, the width, really is    of 24 m.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved.\r
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\n" ); document.write( "\n" ); document.write( "The method I used in the solution, was a kind of the Substitution method.\r
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\n" ); document.write( "Comment from student: Thank you! i was able to figure out the rest of it to find the area. thanks a bunch!
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\n" ); document.write( "\n" ); document.write( "My response : I am glad to hear it (!)\r
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