document.write( "Question 1161991: Cheryl invests her inheritance in 2 separate accounts. She puts part of it in an account
\n" ); document.write( "earning 18% annual interest, and twice that amount in an account earning 12% interest. If
\n" ); document.write( "the account at 12% earns $1200 more interest for the year than the 18% account, what is
\n" ); document.write( "the amount of the inheritance? \n" ); document.write( "

Algebra.Com's Answer #785648 by Theo(13342) $\"\"$ $\"About$

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x = amount invested at 18%
\n" ); document.write( "y = amount invested at 12%
\n" ); document.write( ".12 * y = .18 * x + 1200
\n" ); document.write( "amount invested at 12% is two times the amount invested at 18%, getting you
\n" ); document.write( "y = 2 * x, therefore:
\n" ); document.write( ".12 * 2 * x = .18 * x + 1200
\n" ); document.write( "simplify to get:
\n" ); document.write( ".24 * x = .18 * x + 1200
\n" ); document.write( "subtract .18 * x from both sides to get:
\n" ); document.write( ".06 * x = 1200
\n" ); document.write( "solve for x to get x = 20,000
\n" ); document.write( "to confirm:
\n" ); document.write( "20,000 invested at 18% gives you 3600 interest.
\n" ); document.write( "40,000 invested at 12% gives you 4800 interest.
\n" ); document.write( "4800 is 1200 more than 3600, confirming that the amount invested at 12% gives you 1200 more interest than the amount invested at 18%.
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