document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1161932>Question 1161932</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the average American male is 5'10\" and the standard deviation is 3\", then Yao Ming who is 7'6\" is within___standard deviations of the mean? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #785632 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=785632\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5'10\" is 70 inches<BR>\n" );
document.write( "7'6\"=90 inches<BR>\n" );
document.write( "z=(90-70)/3= 20/3 or 6 2/3 sd s from the mean </SPAN>\n" );
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