document.write( "Question 1161965: In this investigation, you will be estimating the values of and to the nearest hundredths place. \r
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document.write( "(this numbers I need the square root) (√40 √75 √90 √245 √450 √640 √675 )\r
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document.write( " 1. Describe clearly what strategy you plan to use to estimate these values.\r
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document.write( "Reflect on the calculations you made. What general methods or short cuts did you find to make the calculations easier as you did each calculation?\r
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Algebra.Com's Answer #785619 by solver91311(24713) You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I'll do one of these; you can figure out the rest.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Consider \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "we can say\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since 90 is pretty close to the middle of the 81 to 100 interval, 9.5 is a pretty good initial guess for the square root of 90.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A little bit too large, so let's try 9.4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A lot too small compared to our first guess, but now we know that.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since 9.5 squared is significantly closer to 90 than 9.4 squared, the next guess should be closer to 9.5 than 9.4. Let's try the value 9.47.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Close, but still a little small, so\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We are still lower, but closer to the true value than our initial guess of 9.5, but now we know that:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since we have seen that 9.49 is closer than 9.50 and you only have to get to the nearest hundredths place, 9.49 is your answer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Checking the work we see that the calculator value is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "9.4868329805051379959966806332982 which rounds to 9.49. By the way, remember that the calculator value is still an approximation, albeit a much better one than the above process. But the square root of anything that is not a perfect square is an irrational number -- the decimal representation goes on forever and never repeats. The only way to represent the square root of 90 exactly is \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " ![]() \n" ); document.write( " |