document.write( "Question 1161939: To make a 6% acid solution, a chemist mixes some 4% acid solution with 12 L of 10% acid solution. How much of the 4% solution must be added to the 10% solution to make the 6% acid solution? \n" ); document.write( "
Algebra.Com's Answer #785601 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "A typical setup for solving the problem using formal algebra....

\n" ); document.write( "10% of the 12L you start with, plus 4% of the x L you add, yields 6% of the (12+x) L:

\n" ); document.write( "\".10%2812%29%2B.04%28x%29+=+.06%2812%2Bx%29\"

\n" ); document.write( "Solve using basic algebra....

\n" ); document.write( "If a formal algebraic solution is not required, here is a quick and easy way to solve mixture problems like this....

\n" ); document.write( "You are starting with 10% acid and adding 4% acid until the solution is 6% acid.

\n" ); document.write( "Model that by imagining walking on a number line from 10 towards 4, stopping when you get to 6. What fraction of the distance have you gone?

\n" ); document.write( "From 10 to 4 is a distance of 6; from 10 to 6 is a distance of 4. The fraction of the distance you have gone is 4/6 = 2/3.

\n" ); document.write( "That means 2/3 of the final mixture is what you are adding.

\n" ); document.write( "So the 12L you started with is 1/3 of the final mixture; and that means the amount of 4% acid you added (2/3 of the final mixture) was 24L.

\n" ); document.write( "ANSWER: 24L

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