document.write( "Question 107806: Find the equation, in standard form, with all integer coefficients, of the line perpendicular to 3x – 6y = 9 and passing through (-2, -1). \n" ); document.write( "
Algebra.Com's Answer #78560 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! 3x-6y=9 \n" ); document.write( "-6y=-3x+9 NOW WE HAVE TO REDUCE THE -6Y TERM TO Y. \n" ); document.write( "WE DO THIS BY DIVIDING ALL THE TERMS BY -6. \n" ); document.write( "-6y/-6=-3x/-6+9/-6 NOW WE REDUCE WHENEVER POSSIBLE. \n" ); document.write( "y=1/2x-3/2 HERE IT'S EASIER TO DEAL IN DECIMALS THAN FRACTIONS. \n" ); document.write( "y=.5x-1.5 (red line) \n" ); document.write( "the perpendicular line has a slope of -2 ( THIS IS THE NEGATIVE RECIPRICAL OF .5) & PASSING THROUGH (-2,-1) USING THE LINE EQUATIO (Y=mX+b) WHERE m=SLOPE & b= THE Y INTERCEPT. \n" ); document.write( "-1=-2*-2+b \n" ); document.write( "-1=4+b \n" ); document.write( "b=-1-4 \n" ); document.write( "b=-5 \n" ); document.write( "thus the equation is: \n" ); document.write( "y=-2x-5 (green line) \n" ); document.write( " |