document.write( "Question 1161942: One person invests $10,000, one part at 4% and another part at 6%. If your annual income is $520, how much do you invest in each part?
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Algebra.Com's Answer #785586 by josgarithmetic(39620) $\"\"$ $\"About$

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\"One person invests,...\"; \"If your annual income is, ...\";\r
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\n" ); document.write( "\n" ); document.write( "Who is who?\r
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\n" ); document.write( "\n" ); document.write( "If same person, then this works like a two-part mixture.\r
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\n" ); document.write( "\n" ); document.write( "Forget about \"One person\" and \"your\". They are the same person (assumed), someone.\r
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\n" ); document.write( "\n" ); document.write( "Someone invests $10000; part at 4% and the rest at 6% annual rate. He earns $520 in one year of time.\r
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\n" ); document.write( "\n" ); document.write( "x at 6% and 10000-x at 4%. The income or interest from these investments was $520.\r
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\n" ); document.write( "\n" ); document.write( " $\"0.06x%2B0.04%2810000-x%29=520\"$ --------solve this. \n" ); document.write( "

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