document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1161875>Question 1161875</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Assume that a procedure yields a binomial distribution with a trial repeated n=10times. Use either the binomial probability formula to find the probability of k=9successes given the probability q=0.49 of failure on a single trial. Hint: First find the probability of a success, p.\r<BR>\n" );
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document.write( "(Report answer accurate to 4 decimal places.)\r<BR>\n" );
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document.write( "P(X=k)= </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #785583 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=785583\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> so probability of 9 successes with prob. 0.51 for a success<BR>\n" );
document.write( "this is 10 (ways it can happen)0.51^9*0.49^1=0.0114\r<BR>\n" );
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document.write( "alternatively, use 2nd VARS and scroll down to binomialpdf and enter (10,0.51,9) ENTER<BR>\n" );
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