document.write( "Question 1161905: Suppose your textbook is opened at random and the product of the facing page numbers is 71556. To what page is the textbook opened? \n" ); document.write( "
| Algebra.Com's Answer #785543 by jim_thompson5910(35256)      You can put this solution on YOUR website! \n" ); document.write( "An algebraic approach\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = unknown page number \n" ); document.write( "x+1 = page number after page x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x*(x+1) = x^2+x = product of page numbers \n" ); document.write( "x^2+x = 71556 \n" ); document.write( "x^2+x-71556 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use the quadratic formula (with a = 1, b = 1, c = -71556) to find the two solutions to be x = 267 and x = -268. Ignore the negative x value, because we can't have negative page numbers.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, the only practical solution is x = 267. The pages we've opened the book to are 267 and 268. \n" ); document.write( "We see that 267*268 = 71556 which confirms the answer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Factoring or graphing is an alternative to solve x^2+x-71556 = 0; though both aren't really feasible by hand. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A non-algebraic approach is to look at the prime factorization of 71556 \n" ); document.write( "71556 = 2*2*3*67*89\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then group those factors into two groups, call them left and right group \n" ); document.write( "One such arrangement is \n" ); document.write( "left group = {2,2,3} \n" ); document.write( "right group = {67,89} \n" ); document.write( "The ordering of any particular single grouping does not matter.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then multiply out each of the two groups \n" ); document.write( "left group's product = 2*2*3 = 12 \n" ); document.write( "right group's product = 67*89 = 5963 \n" ); document.write( "the results of each group will then be the two page numbers; however, notice that 12 and 5963 are not adjacent pages. Also, it is unlikely a textbook has 5963 pages or more.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then another arrangement is \n" ); document.write( "left group = {2,67,3} \n" ); document.write( "right group = {2*89} \n" ); document.write( "left group's product = first page number = 2*67*3 = 402 \n" ); document.write( "right group's product = second page number = 2*89 = 178 \n" ); document.write( "We again get non-adjacent page numbers. At least the values are reasonable for any textbook.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the idea is to guess and check. It turns out after a bit of trial and error you should find that \n" ); document.write( "left group = 3*89 = 267 \n" ); document.write( "right group = 2*2*67 = 268 \n" ); document.write( "I used the previous section to help get to this quickly. If you didn't have that as a guide, then it would take longer. Though it's still a somewhat feasible route. \n" ); document.write( "The recommendation I have is to make sure 67 and 89 are not in the same group. Otherwise their product will multiply to 67*89 = 5963 (or larger if other factors are involved). \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |