document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1161840>Question 1161840</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve by substitution: \r<BR>\n" );
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document.write( "y=(5/8)x+4<BR>\n" );
document.write( "16y+3x=-40 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #785525 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=785525\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y=(5/8)x+4 <BR>\n" );
document.write( "16y+3x=-40<BR>\n" );
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document.write( "Sub for y in the 2nd eqn<BR>\n" );
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document.write( "Multiply the 1st eqn by 16 to avoid fractions:<BR>\n" );
document.write( "16y = 10x + 64<BR>\n" );
document.write( "16y + 3x = -40<BR>\n" );
document.write( "--<BR>\n" );
document.write( "Then sub for 16y in the 2nd eqn<BR>\n" );
document.write( " </SPAN>\n" );
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