document.write( "Question 1161686: The average number of milligrams (mg) of sodium in a certain brand of low-salt microwave frozen dinners is 660 mg, and the standard deviation is 35 mg. Assume the variable is normally distributed.\r
\n" ); document.write( "\n" ); document.write( "a. If a single dinner is selected, find the probability that the sodium content will be more than 670 mg. \r
\n" ); document.write( "\n" ); document.write( "b. If a sample of 10 dinners is selected, find the probability that the mean of the sample will be larger than 670 mg.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #785429 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
z=(x-mean)/sd
\n" ); document.write( "for a single dinner, z would be (670-660)/35 or 0.29 with probability 0.3875 (using 2/7 for z)\r
\n" ); document.write( "\n" ); document.write( "for 10 dinners z=(x bar-mean)/sigma/sqrt(10)
\n" ); document.write( "this is z>(2/7)*sqrt(10)=0.9035. That probability is 0.1831
\n" ); document.write( "
\n" );